Find the value of x in each triangle below.

The area of a triangle is derivable from the product of two adjacent sides times the sin of the included angle of the two sides or A = absin(C).
 
TchrWill said:
The area of a triangle is derivable from the product of two adjacent sides times the sin of the included angle of the two sides or A = absin(C).
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Dear Sir/Ma'am,

I would like to thank you for what your signature is telling me. I've been trying to stick to it , since when I saw it.

My Regards.

Burak
 
burakaltr said:
OK.

Consider 2 lengths ( adjacent ) * the Sine of the Angle between= 2* AREA of Triangle
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On second thought , I think I need to be clearer on this :

For ABC triangle

a*b*Sin(C)/2

a*c*Sin(B)/2

b*c*Sin(A)/2

All of the above yield the Area

also Heron's formulae applies

When u=(a+b+c)/2 is known ( half-perimeter )

(Area)**2=u*(u-a)*(u-b)*(u-c)
 
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