Help with proof. (Appears last one failed to post.)

[Mpc]

I need to do a proof from this:

​< link to objectionable page removed >

 

[Mrspi]

I need to do a proof from this: <link removed>

Did you notice that the angles numbered <1 and <5 are corresponding angles formed when lines AB and FD are cut by transversal EB.

If you can show that <1 and <5 are congruent, then you can use the postulate (or theorem, depending on your text) which says that if two lines are cut by a transversal so that a pair of corresponding angles are congruent, the lines are parallel.

You have two triangles...one pair of angles in those triangles is GIVEN congruent.

Another pair of angles are formed by a couple of sets of perpendicular lines. What kind of angles are formed by perpendicular lines? That should allow you to establish that the angles in this second pair are congruent.

AND...if two angles of one triangle are congruent to two angles of another triangle, what can you say about the THIRD pair of angles in those triangles?

(The third pair of angles, by the way, would consist of the angles we're interested in....angles 1 and 5.)

So...there it is, an outline for your two-column proof. I hope you can follow that outline and write the proof yourself.

 

[Deleted member 4993]

I need to do a proof from this: <link removed>

The problem states that FE is perpendicular to EB and AB is perpendicular to EB.

Is that correct?

 

[Mrspi]

The problem states that FE is perpendicular to EB and AB is perpendicular to EB.

Is that correct?

I did not even notice that! I think that obviously there is a typo....

If the perpendiculars really ARE as stated in the problem, I don't think it is possible to prove that AB || FD.

Good catch.

 

[ankitvermajnp]

If so then angle 6 and angle 1 both are 90 at the same base then both are parallel to each other and because angle 2 is equal to angle 4 so line AB will parallel to FD