Unable to solve this Trig question

[ak992]

I have been trying for hours to solve this problem however I am unable to use any trig function to solve the problem.

I am trying to find out the diameter of the circular tank.

From point X to the tank is 101.527M (Which on photo is labeled R)

The Angle AXO is 17'10'40"
Angle XAO is 90'

Here is the link to the picture - https://db.tt/aRY0991d

I have tried going down the similar triangle route however I didn't have much luck.

I have attached a photo and any help would be much appreciated.

 

[stapel]

I have been trying for hours to solve this problem however I am unable to use any trig function to solve the problem.

I am trying to find out the diameter of the circular tank.

From point X to the tank is 101.527M (Which on photo is labeled R)

The Angle AXO is 17'10'40"
Angle XAO is 90'

Here is the link to the picture - https://db.tt/aRY0991d

I have tried going down the similar triangle route however I didn't have much luck.

I have attached a photo and any help would be much appreciated.

To other viewers: To replicate the picture, draw an horizontal line segment with point X at the left-hand end and point O at the right-hand end. Draw a circle, centered on O, cutting XO maybe about one-fifth of the way from O to X; label the intersection point on XO as R. Draw lines from X to tangency points on either side of the circle; label the upper tangent intersection point as A; label the lower tangent intersection point as B. Draw the radius lines and label the right angles. Label the segment RX as 101.527m; label the angle AXR as 17° 10' 40".

To the original poster: Please reply with a clear listing of your efforts so far. In particular, please clarify what "similar triangles" you were attempting to use. For instance, you noted that the length of the hypotenuse of the right triangle AOX was r + 101.527 and the height was r. You noted that these two sides relate to the sine ratio. You noted that the angle measure is equivalent to 17-and-8/45 degrees. And... then what?

Please be complete. Thank you!