Hi, this is a question I have been set to do over the Christmas break:
1. The ellipse E has the following equation:
. . . . .\(\displaystyle \dfrac{x^2}{a^2}\, +\, \dfrac{y^2}{b^2}\, =\, 1\)
Two points, P and Q, on E have the following coordinates:
. . . . .\(\displaystyle \left(a\, \cos(\theta),\, b\, \sin(\theta)\right)\)
. . . . .\(\displaystyle \left(-a\, \sin(\theta),\, b\, \cos(\theta)\right)\)
Show that the equations of the tangents at P and Q are as follows:
. . . . .\(\displaystyle \left(b\, \cos(\theta)\right)\, x\, +\, \left(a\, \sin(\theta)\right)\,y\, =\, ab\)
. . . . .\(\displaystyle \left(-b\, \sin(\theta)\right)\, x\, +\, \left(a\, \cos(\theta)\right)\,y\, =\, ab\)
2. These two tangents meet at point T. Find the coordinates of T. Show that T lies on the ellipse F with the following equation:
. . . . .\(\displaystyle \dfrac{x^2}{2a^2}\, +\, \dfrac{y^2}{2b^2}\, =\, 1\)
The first question I managed to do quite easily: just a matter of differentiation parametrically and finding the tangents. But I have no idea how to tackle the second question. I tried to equate the two tangents I'd found, but I couldn't simply to find the coordinates. I'm pretty sure these are in terms of a's, b's, and trig.
Thanks for help in advance!
1. The ellipse E has the following equation:
. . . . .\(\displaystyle \dfrac{x^2}{a^2}\, +\, \dfrac{y^2}{b^2}\, =\, 1\)
Two points, P and Q, on E have the following coordinates:
. . . . .\(\displaystyle \left(a\, \cos(\theta),\, b\, \sin(\theta)\right)\)
. . . . .\(\displaystyle \left(-a\, \sin(\theta),\, b\, \cos(\theta)\right)\)
Show that the equations of the tangents at P and Q are as follows:
. . . . .\(\displaystyle \left(b\, \cos(\theta)\right)\, x\, +\, \left(a\, \sin(\theta)\right)\,y\, =\, ab\)
. . . . .\(\displaystyle \left(-b\, \sin(\theta)\right)\, x\, +\, \left(a\, \cos(\theta)\right)\,y\, =\, ab\)
2. These two tangents meet at point T. Find the coordinates of T. Show that T lies on the ellipse F with the following equation:
. . . . .\(\displaystyle \dfrac{x^2}{2a^2}\, +\, \dfrac{y^2}{2b^2}\, =\, 1\)
The first question I managed to do quite easily: just a matter of differentiation parametrically and finding the tangents. But I have no idea how to tackle the second question. I tried to equate the two tangents I'd found, but I couldn't simply to find the coordinates. I'm pretty sure these are in terms of a's, b's, and trig.
Thanks for help in advance!
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