Trig problem!! need urgent help

need help on solving for dc, bc, ab see attachment; already know first

I've done this: http://prnt.sc/a3v8o7
attachment.php


How did you calculate AC? Please show work - so that we know where to start telling you about the process involved.
 
need help on solving for dc, bc, ab see attachment
I will assume that you mean "DC, BC, and AB" (since lower-case would be something else), and that you mean that you've found the values for AC and AD.

I'm sorry, but I can't discern anything on this blurry image.

Your exercise is as follows:

attachment.php


I will guess that you applied the Law of Sines to the triangle ACF. You subtracted to find the value of the third angle, CAF. Then you used the given length of AF and the various angle values to obtain the value for AC. Then you applied the same process to the triangle ADE, using the length of AE and the angle values to find the length of AD.

You now need to find the length of DC. You've drawn the diagonal across the quadrilateral ADBC, forming the new triangle ADC. You have the values for AD and AC. You have the angle values for DAE, EAF, and FAC, so you subtracted to obtain the value of the angle DAC. Then you applied the Law of Cosines to find the value of DC. And... then what?

Please be complete. Thank you! ;)
 
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