Cot2theta= cot^2theta-1 over 2cottheta
Choose the sequence of steps that vary the identity
3squareroot 2 cos theta+1=-2
What is the solution set in the interval 0 <(with a line under it) theta < 2pi
What are your thoughts? What have you done so far? Please show us your work even if you feel that it is wrong so we may try to help you. You might also read
http://www.freemathhelp.com/forum/threads/78006-Read-Before-Posting
I assume you mean
Prove
(1) \(\displaystyle cot(2\theta)\, =\, \frac{cot^2(\theta)-1}{2\, cot(\theta)}\)
and
Solve for \(\displaystyle \theta\)
(2) \(\displaystyle 3\, sqrt{2}\, cos(\theta)\, +\, 1\, =\, -2\)
If that is not the case, please use grouping symbols for your equations to make the plainer and restate the problem as to what the actual questions are.
If it is the case, for (1) I would start with changing the initial cot(\(\displaystyle 2\, \theta\)) into sines and cosines, use the sum formulas for the sine and cosine, and proceed from there. For (2) I would first simplify the equation, then remember that cos(-x)=cos(x) and the cosine has a period of 2\(\displaystyle \pi\).