When you're asking people for help, it might be nice if you did them the respect of speaking clearly...? :roll:
hihihihihi said:
1) 5(x-7)^2=135
2) the yd is 80 ft by 100 ft u r planning a flower bed around of uniform width around the yard .if you want ur lawn to be 1/20th the area of your original yard wht is the width of the flower bed..
3) 2 people leave at the same time at a right angle 2 hrs the walkers are 10 miles apart if the first walker walks 1mph faster than the other wht speed is each walker traveling?/
1) I will guess that you mean "Solve the equation 5(x - 7)^2 = 135 for the values of x". If so:
Divide through by 5, take the square root of either side (remembering the "plus-minus" bit), and then add 7 to either side.
2) I will guess that you mean the following:
"A yard is eighty feet by one hundred feet. You are planning a flower bed, of uniform width, to go round the edges of (but inside) this yard. If you want the lawn area to cover one-twentieth of the area of the original yard (so that 1/20 of the yard is turf, and 19/20 is flowers), what should be the width of the yard?"
(I would also guess that the assignment phrased the question something like this, with standard punctuation, spelling, capitalization, and grammar. Few are the textbooks which resort to cutesy-kiddie chat-speak.)
If so, then start by drawing a picture, and labelling the length and width with the given values. Find 1/20 of this area. Draw an inner rectangle, demarking the turf from the flowers. Label the width of the flowered area with a variable, and contruct an equation equating the 1/20 value you found, and the expression for the total area of the walk.
If not, please reply with (understandable) corrections.
In either case, please show what you have tried, and how far you have gotten.
3) I will guess that the exercise was something along the lines of:
"Two people leave the same point at the same time, and head off at right angles to each other. After two hours of walking, the walkers are ten miles apart. If the first walker walks one mile an hour faster than the other, what is the speed of each walker?"
If so, then draw the picture, noting that you have a right-angled triangle. Pick a variable for the rate of the second walker. Use the fact that the other goes one mile an hour faster, and create an expression for the rate of the other walker. Multiply the rates by the time to get "distance" expressions for each. Label the triangle appropriately. Then apply the Pythagorean Theorem to the right-angled triangle, setting the hypotenuse equal to "10". Solve for the variable.
If not, please reply with (understandable) corrections.
In either case, please show what you have tried and how far you have gotten.
Thank you.
Eliz.
