a*cos(180*deg - beta) + b*sin(gamma-(beta-90*deg) = d

penguin1996

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Feb 8, 2016
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Hello everyone,

I need your help. I'm sitting around by solving this since yesterday but I'm too blunt. can someone help me please?

a*cos(180*deg - beta) + b*sin(gamma-(beta-90*deg) = d

a*sin(180*deg - beta) - b*cos(gamma-(beta-90deg)=h

0≤beta≤180 and 0≤gamma≤180
Help me please :(

 
Hello everyone,

I need your help. I'm sitting around by solving this since yesterday but I'm too blunt. can someone help me please?

a*cos(180*deg - beta) + b*sin(gamma-(beta-90*deg) = d

a*sin(180*deg - beta) - b*cos(gamma-(beta-90deg)=h

0≤beta≤180 and 0≤gamma≤180
Help me please :(

 
a*cos(180*deg - beta) + b*sin(gamma-(beta-90*deg) = d

a*sin(180*deg - beta) - b*cos(gamma-(beta-90deg)=h
You have two equations in six unknowns. How are you intending to "solve" this?

When you reply, please include the full and exact exercise statement, the complete instructions, and a clear listing of your thoughts and efforts so far, so we can see what is going on. Thank you! ;)
 
You have two equations in six unknowns. How are you intending to "solve" this?

When you reply, please include the full and exact exercise statement, the complete instructions, and a clear listing of your thoughts and efforts so far, so we can see what is going on. Thank you! ;)


Well, the problem is, that there is no exact exercise statement. The exercise says only

"Given:a*cos(180*deg - beta) + b*sin(gamma-(beta-90*deg) = d

a*sin(180*deg - beta) - b*cos(gamma-(beta-90deg)=h

Find beta and gamma".

That's it. Maybe I have to put beta and the gamma in each equation to one side and other terms to the other? but I don't know how. I'm really in doubt
:(:confused:
 
You have two equations in six unknowns. How are you intending to "solve" this?

When you reply, please include the full and exact exercise statement, the complete instructions, and a clear listing of your thoughts and efforts so far, so we can see what is going on. Thank you! ;)



a and b are constants, d and h are variables. is it possible to describe my beta and gamma through this equations?
 
What is the meaning of the asterisks? One could argue that you mean "degrees" or "multiplication", but surely not both in the same equation...? :oops:

When you reply, please show what you have tried so far, even if you think it's wrong. Thank you! ;)
 
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