Advanced Algebra 8th grade

[Cheerleader123]

I am having a problem with one of my math problems. Well actually, i dont understand it at all... And so i was wondering if anyone could help me.
Thank you.
~cheerleader123

This is my math problem:

At 10:00AM a car leaves a house at a rate of 60mi/h. At the same time, another car leaves the same house at a rate of 50 mi/g. in the opposite direction. At what time will the cars be 330 miles apart?

please help me as soon as possibe.
Thanks.

 

[Cheerleader123]

8th grade advanced algebra problem.

I dont even know how to get started with this problem. It is giving me alot of trouble.

 

[skeeter]

(distance 1st car travels) + (distance 2nd car travels) = 330

also ... (rate of speed)(time traveled at that speed) = distance

both cars travel for the same amount of time in hours ... call it "t". now use the information given above to set up an equation and solve for "t".

 

[Loren]

At 10:00AM a car leaves a house at a rate of 60mi/h. At the same time, another car leaves the same house at a rate of 50 mi/g. in the opposite direction. At what time will the cars be 330 miles apart?

Sometimes a sketch will help.

.............60mph.......................50mph
|------------------------------|----------------------|
|<------------------330 mi ---------------------->|

d=rt

d1=60t
d2=50t
d1+d2=330
Can you finish?

 

[Denis]

In its simplest terms:
if you're travelling @ 110 mph, how long does it take you to travel 330 miles?