So, my class was given a "Square Root" function consisting of four ordered pairs that look like a square root. I'll call this function f(x). We are then asked to perform various transformations on f(x). I've already turned this in, and just got it back today with one question wrong and I'm not sure why...I'm hoping somebody here can help!
The original ordered pairs of the "Square Root" function f(x) are (-4,2), (-2,2), (0,0), and (2,4).
The transformation I'm lost on is:
(1/2)f([-1/2]x+2)+3
Here is what I've done:
1st - I factored out (-1/2) to get: (1/2)f([-1/2][x-4])+3
2nd - I applied the transformations required point by point in the following order:
-Shifted the point right 4 units.
-Stretched the point horizontally by a factor of 2.
-Reflected the point about the y-axis.
-Shrunk the point vertically by a factor of 2.
-Shifted the point up 3 units.
I ended up with the following ordered pairs: (0,4), (-4,4), (-8,3), and (-12,5).
Somewhere I've gone wrong, and I can't figure out where. Any help would be greatly appreciated!
-Perry Campbell
(Student @ Seattle Central CC)
The original ordered pairs of the "Square Root" function f(x) are (-4,2), (-2,2), (0,0), and (2,4).
The transformation I'm lost on is:
(1/2)f([-1/2]x+2)+3
Here is what I've done:
1st - I factored out (-1/2) to get: (1/2)f([-1/2][x-4])+3
2nd - I applied the transformations required point by point in the following order:
-Shifted the point right 4 units.
-Stretched the point horizontally by a factor of 2.
-Reflected the point about the y-axis.
-Shrunk the point vertically by a factor of 2.
-Shifted the point up 3 units.
I ended up with the following ordered pairs: (0,4), (-4,4), (-8,3), and (-12,5).
Somewhere I've gone wrong, and I can't figure out where. Any help would be greatly appreciated!
-Perry Campbell
(Student @ Seattle Central CC)