Angle CAB=45°; angle CBA=15°. Point M is from AB and AM:MB=1:2. Angle BMC=?°

Nikolasekulov

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Angle CAB=45°; angle CBA=15°. Point M is from AB and AM:MB=1:2. Angle BMC=?°

My homework problem:

Angle CAB=45°; angle CBA=15°. Point M is from AB and AM:MB=1:2. Angle BMC=?°.

Please help!
 
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Angle CAB=45°; angle CBA=15°. Point M is from AB and AM:MB=1:2. Angle BMC=?°.
We cannot see whatever it is that you're looking at. In particular, I suspect that A, B, C, and M are all on one "figure", but what kind of figure is this? One triangle? An assemblage of line segments? Something else?

When you reply with clarification, please include a clear listing of your thouights and efforts so far, so we can see where you're getting stuck. Thank you! ;)
 
If that's a triangle, then looks like this:
Code:
        (120)
           C




(45)                                   (15)
A      1        M           2            B
You have sufficient information to calculate angle BMC.

Did your teacher not show up to teach this?

No he has not and yes, this is how the drawing look like.Do you know how to do it?
 
We cannot see whatever it is that you're looking at. In particular, I suspect that A, B, C, and M are all on one "figure", but what kind of figure is this? One triangle? An assemblage of line segments? Something else?

When you reply with clarification, please include a clear listing of your thouights and efforts so far, so we can see where you're getting stuck. Thank you! ;)
ABC is a triangle.
 
Yes, using trigonometry. Haven't tried using geometry only.
YOU find out what's expected: we're not here to guess.
And show YOUR work: we don't give out full solutions,
unless you give us your teacher's email to confirm it's ok.
This problem I found in my studentbook for eight grade so I guess that I should build something and belive me I have tried many many things. I don't need a full solution just a hint what should I build. If you manage to solve it just give me that hint please.
 
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