Alright. I know that the area of an equilateral triangle is (side)^2 (sqrt(3)/4)
however, I was doing a problem, and started it without remembering that fact. I was given that a side of the triangle is 2sqrt(x), so I broke the triangle into two right triangles with leg = sqrt(x) and hypotenuse = 2sqrt(x)
Using Pythagorean Theorem, I found a height of sqrt(3x). Then, I doubled the area formula for standard triangles to get A = b times h
My final answer was sqrt(3x^2)
Could I get an explanation of how this approach doesn't make sense?
however, I was doing a problem, and started it without remembering that fact. I was given that a side of the triangle is 2sqrt(x), so I broke the triangle into two right triangles with leg = sqrt(x) and hypotenuse = 2sqrt(x)
Using Pythagorean Theorem, I found a height of sqrt(3x). Then, I doubled the area formula for standard triangles to get A = b times h
My final answer was sqrt(3x^2)
Could I get an explanation of how this approach doesn't make sense?
