Cant find angle

[Zulgok]

Hi, I have to find angle /ACB, but Im not sure how. Lenght AC=AB and lenght AO=AB=BO. From that, I made /ABO=/AOB=/OAB=60 degrees. If possible, could I receive one simple hint ? Thank you

 

[pka]

Hi, I have to find angle /ACB, but Im not sure how. Lenght AC=AB and lenght AO=AB=BO. From that, I made /ABO=/AOB=/OAB=60 degrees. If possible, could I receive one simple hint ?

The measure of the circular arc \(\displaystyle AB\) has the same measure as \(\displaystyle \angle AOB\)

 

[Zulgok]

So /A and /B are actually 90 degrees ? If so, it means I already had the answer

 

[Zulgok]

90 degrees I meant /A from both sides, not on one And yes, got my final answer same as yours.

 

[Deleted member 4993]

All radial segments meet at a tangent contact point at right angles.
\(\displaystyle m\left( {\angle ACB} \right) = \frac{{2\pi }}{3} = \frac{1}{2}\left( {\max \widetilde {AB} - \min \widetilde {AB}} \right)\)

All radial segments meet at a tangent contact point at right angles.

\(\displaystyle m\left( {\angle ACB} \right) = \frac{{2\pi }}{3} = \frac{1}{2}\left( {\max \widetilde {AB} - \min \widetilde {AB}} \right)\)