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convert the equation to polar co-ordinates (follow-up)
- Thread starter TheBit
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The post you quoted did not contain any "steps". Please reply with a complete listing of your own efforts, clearly specifying at which "step" you are getting stuck. Thank you!
I think the step you're having trouble understanding is the same one that 81ttopcoupe was having trouble understanding back in 2011 - that being the first step in Subhotosh Khan's post. If that's not right, please correct me. The equation in question says:
\(\displaystyle r \cdot sin(\theta)=r^2 \cdot cos^2(\theta)\)
Both sides have an r term, so what if you divide by r?
\(\displaystyle sin(\theta)=r \cdot cos^2(\theta)\)
Now, how would you solve the above equation for r?
\(\displaystyle r \cdot sin(\theta)=r^2 \cdot cos^2(\theta)\)
Both sides have an r term, so what if you divide by r?
\(\displaystyle sin(\theta)=r \cdot cos^2(\theta)\)
Now, how would you solve the above equation for r?