factoring a quadratic: 2y^2 + 20y + 80

Re: factoring a problem

cjswonderfulgirl said:
i know this is probably a no-brainer, but i'm having serious trouble factoring this one...2y^2 +20y+80
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There happens to be no factors in the real numbers.
Using complex numbers we can factor it.
Do you want that?
 
Re: factoring a problem

no, i got it wrong, so now i have a new problem and i'm using the quadratic formula :(
 
Re: factoring a problem

cjswonderfulgirl said:
no, i got it wrong, so now i have a new problem and i'm using the quadratic formula :(
Click to expand...
What new problem? What are you saying?
I see no difference in the question.
 
Re: factoring a problem

no, i mean i do my homework online and i got the problem wrong, so they gave me a new question. i figured it out, though, but thanks a lot for letting me in on the fact that there were no real factors:)
 
cjswonderfulgirl said:
...'m having serious trouble factoring this one: 2y^2 + 20y + 80
Click to expand...

Um... maybe take the common factor of "2" out front...? :shock:

Eliz.
 
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