Find the 1/8 perimeter of this trapezoid

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stevecowall

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Question: The area of a trapezoid with integral sides is 124. If exactly two of its angles are right angles, find 1/8 of its perimeter.

Untitled.png

What i have been working on so far:
I'm not sure if my picture is correct. Well, I started with the area equation which is
1/2 x (b1+b2) x h = 124
b1+b2 = 248/h by simplifying it

and finding the perimeter solution is
b1+b2+s1+h = P
b1+b2 = P - s1 - h

Now using transitive I got 248/h = P -s1 -h

And now i can't figure out what to do next ...
 
Last edited:
stevecowall said:
Question: The area of a trapezoid with integral sides is 124. If exactly two of its angles are right angles, find 1/8 of its perimeter.

View attachment 1498

What i have been working on so far:
I'm not sure if my picture is correct. Well, I started with the area equation which is
1/2 x (b1+b2) x h = 144
b1+b2 = 288/h by simplifying it

and finding the perimeter solution is
b1+b2+s1+h = P
b1+b2 = P - s1 - h

Now using transitive I got 266/h = P -s1 -h

And now i can't figure out what to do next ...
Click to expand...

You've got ME totally confused....your numbers keep changing. First, the area is 124....and then it becomes 144, which produces a 288 that later becomes 266.

Before I invest any more time in trying to figure out what to do, PLEASE correct what you've typed!
 
Find the 1/8 perimeter of this trapezoid

Question: The area of a trapezoid with integral sides is 124. If exactly two of its angles are right angles, find 1/8 of its perimeter.

Attachment 1498

What i have been working on so far:
I'm not sure if my picture is correct. Well, I started with the area equation which is
1/2 x (b1+b2) x h = 124
b1+b2 = 248/h by simplifying it

and finding the perimeter solution is
b1+b2+s1+h = P
b1+b2 = P - s1 - h

Now using transitive I got 248/h = P -s1 -h
Click to expand...

I do not see a unique solution.

Is there any additional information in the problem statement or drawing?
 
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