find the root of f(x)=x^2+x-6

[dayton1]

find the root of the function:

The instructor said I was on the right track by setting this equal to 0

f(x)=x^2+x-6

0=x^2+x-6

(x-3)(x+2)

x=3 or x=-2

...but I got it wrong....I'm not sure what he is asking

 

[dayton1]

Sorry I am asking so many questions today, but the teacher told us he wrote this exam way too hard and everyone failed....so it's up to us to do corrections.....arghhh!

 

[o_O]

If you expand (x-3)(x+2), do you get x² + x - 6 again?

 

[dayton1]

Oh whoops. so is it: (x+3)(x-2)

X=-3 or x=2???

 

[o_O]

There ya go :wink:

 

[Denis]

Oh whoops. so is it: (x+3)(x-2)
X=-3 or x=2???

WHY are you not sure?
Check yourself by substituting these in the original equation.