Find y′(x) for the curve sin(x^2 + y^2) = x^2 + y^2.
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pka
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If \(\sin(x^2+y^2)=x^2+y^2\) then first find the implicit derivatives.
\([\cos(x^2+y^2)][2x+2yy^{\prime}]=[2x+2yy^{\prime}]\)
This is not a homework service. We are glad to help you.
But you must show us the results. I did the calculus.
So you now do the elementary algebra: solve for \(y^{\prime}\) and post the result.
\([\cos(x^2+y^2)][2x+2yy^{\prime}]=[2x+2yy^{\prime}]\)
This is not a homework service. We are glad to help you.
But you must show us the results. I did the calculus.
So you now do the elementary algebra: solve for \(y^{\prime}\) and post the result.
topsquark
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- Aug 27, 2012
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Can we back up a moment with this? So far as I know the equation [math]x^2 + y^2 = sin( x^2 + y^2 )[/math] has only one solution: (x, y) = (0, 0). So the "curve" can't have a first derivative. Except as an exercise the question is meaningless.
-Dan
-Dan