stevecowall
New member
- Joined
- Nov 9, 2011
- Messages
- 34
Questions:
The diagonals of a rhombus have length 18 and 20. What is the perimeter of the rhombus?
My solution:
When the two diagonals of a rhombus intersect, it creates a four right triangle. And the sides of the triangle will be 18/2 = 9 and 20/2 = 10.
Using pythagorean theorem, Square Root of (92+102) = square root of 181
But there are four sides which are equal to each other so 4*(square root of 181) = 53.814
The diagonals of a rhombus have length 18 and 20. What is the perimeter of the rhombus?
My solution:
When the two diagonals of a rhombus intersect, it creates a four right triangle. And the sides of the triangle will be 18/2 = 9 and 20/2 = 10.
Using pythagorean theorem, Square Root of (92+102) = square root of 181
But there are four sides which are equal to each other so 4*(square root of 181) = 53.814