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FINDING THE HYPOTENUSE OF A RIGHT TRIANGLE
- Thread starter caspen7.0
- Start date
Hello, caspen7!
Why are you shouting?
You know two angles and the included side.
Obviously, the "included side" is not the hypotenuse,
So the two known angles are: one of the acute angles and the right angle.
\(\displaystyle \text{So we know: }\:\angle A,\;\text{ side }b,\;\angle C = 90^o\)
\(\displaystyle \text{Then: }\:\cos A \:=\:\frac{b}{c}\)
\(\displaystyle \text{Therefore: }\:c \;=\;\frac{b}{\cos A}\)
Why are you shouting?
I NEED TO FIND THE HYPOTENUSE OF A RIGHT TRIANGLE
I HAVE THE 2 ANGLES AND THE INCLUDED SIDE
ONE OF THE ANGLES AND THE SIDE REMAIN SAME. . What does this mean?
You know two angles and the included side.
Obviously, the "included side" is not the hypotenuse,
So the two known angles are: one of the acute angles and the right angle.
Code:
o B
* |
c * |
* |
* |
* |
A * - - - - - - - - - - - * C
b\(\displaystyle \text{So we know: }\:\angle A,\;\text{ side }b,\;\angle C = 90^o\)
\(\displaystyle \text{Then: }\:\cos A \:=\:\frac{b}{c}\)
\(\displaystyle \text{Therefore: }\:c \;=\;\frac{b}{\cos A}\)
Caspen, if you don't get serious, you'll end up flipping burgers at Burger King...caspen7.0 said:LOL sry
Time to quit silly chatboard stuff like "LOL", and time to start spelling words IN FULL: sry = sorry.
Believe me, you won't regret it later...