This is a real life math problem I have. Any help is welcomed.
There are three forces (P, R1 and R2) that meet at a point called the origin (0,0,0) in a three-dimensional space. All three forces are in the same plane and are separated from each other by exactly 120 degrees. The initial magnitude of each force is P = 440.6484, R1 = 254.8257 and R2 = 359.4929. Each force starts at a point 1.154700 units from the origin, for example, force P starts at P[c] located at 1.154700, 0, 0. Force R1 starts at R1[c] located at -0.816496, 0.81696, 0 and force R2 starts at R2[c] located at -0.816496, -0.816496, 0. The magnitude of each force can change based on its direction as follows:
Force P - Draw a line from P[c] to point A located at 3.154700, 0, 0 . The initial angle (A-P[c]-Origin) is 180 degrees. The magnitude of the Force P = cos(x + 0.0664431)*440.6487394, where x is the angle A-P[c]-Origin.
Force R1 - Draw a line from R1[c] to point B located at 0, 0, 1.632993. The initial angle (B-R1[c]-Origin) is 54.735610 degrees. The magnitude of Force R1 = -cos(180 -y + 0.0664431)*440.6487394, where y is the angle B-R1(c)-Origin.
Force R2 - Draw a line from R2[c] to point C located at 0, 0, -1.632993. The initial angle (C-R2[c]-Origin0 is 54.735610 degrees. The magnitude of Force R2 = -cos(270 - z +0.066431)*440.6487394, where z is the angle C-R[2]-Origin.
What is the point where the three forces balance exactly?
More information is here: rooseveltsTOE.blogspot.com/2015/10/section-231-mass-of-mesons-and-other.html
There are three forces (P, R1 and R2) that meet at a point called the origin (0,0,0) in a three-dimensional space. All three forces are in the same plane and are separated from each other by exactly 120 degrees. The initial magnitude of each force is P = 440.6484, R1 = 254.8257 and R2 = 359.4929. Each force starts at a point 1.154700 units from the origin, for example, force P starts at P[c] located at 1.154700, 0, 0. Force R1 starts at R1[c] located at -0.816496, 0.81696, 0 and force R2 starts at R2[c] located at -0.816496, -0.816496, 0. The magnitude of each force can change based on its direction as follows:
Force P - Draw a line from P[c] to point A located at 3.154700, 0, 0 . The initial angle (A-P[c]-Origin) is 180 degrees. The magnitude of the Force P = cos(x + 0.0664431)*440.6487394, where x is the angle A-P[c]-Origin.
Force R1 - Draw a line from R1[c] to point B located at 0, 0, 1.632993. The initial angle (B-R1[c]-Origin) is 54.735610 degrees. The magnitude of Force R1 = -cos(180 -y + 0.0664431)*440.6487394, where y is the angle B-R1(c)-Origin.
Force R2 - Draw a line from R2[c] to point C located at 0, 0, -1.632993. The initial angle (C-R2[c]-Origin0 is 54.735610 degrees. The magnitude of Force R2 = -cos(270 - z +0.066431)*440.6487394, where z is the angle C-R[2]-Origin.
What is the point where the three forces balance exactly?
More information is here: rooseveltsTOE.blogspot.com/2015/10/section-231-mass-of-mesons-and-other.html