A cable pulls on a flange with a tension force to northeast. Using the slop triangle method solve for the horizontal and vertical components of the tension force.
so arrow points up and to the right with 500N at end of it showing the tension force. There is a triangle drawn on the rope that gives you the two sides 5 and 12. 12 being vertical and 5 being horizontal.
F(x)=a/c * F(R)
F(y)=b/c * F(R)
x = 5/13*500= 192.3N
y= 12/13*500=461.53N
This is what I came up with. The teacher didn't give any examples just talked about newtons law assigned homework and said seeya later. So I don't have much to reference other than the confusing book and the answers in the back of the book. and I'm not getting the answer to match whats in the back So I could use some help please.
Answer in back says F(x) = 1.8kip<
F(y) = 2.4kip^
I forget what kips are but I feel like this must be wrong since its not in Newtons like the problem is maybe the book was mistyped? or i'm just really not getting it..
so arrow points up and to the right with 500N at end of it showing the tension force. There is a triangle drawn on the rope that gives you the two sides 5 and 12. 12 being vertical and 5 being horizontal.
F(x)=a/c * F(R)
F(y)=b/c * F(R)
x = 5/13*500= 192.3N
y= 12/13*500=461.53N
This is what I came up with. The teacher didn't give any examples just talked about newtons law assigned homework and said seeya later. So I don't have much to reference other than the confusing book and the answers in the back of the book. and I'm not getting the answer to match whats in the back So I could use some help please.
Answer in back says F(x) = 1.8kip<
F(y) = 2.4kip^
I forget what kips are but I feel like this must be wrong since its not in Newtons like the problem is maybe the book was mistyped? or i'm just really not getting it..