Given triangle ABC with right angle <BAC AD perpendicular to BC BD= 3, AD=5, DC=?
Z zzlady12 New member Joined Apr 5, 2010 Messages 1 Apr 5, 2010 #1 Given triangle ABC with right angle <BAC AD perpendicular to BC BD= 3, AD=5, DC=?
M masters Full Member Joined Mar 30, 2007 Messages 378 Apr 5, 2010 #2 zzlady12 said: Given triangle ABC with right angle <BAC AD perpendicular to BC BD= 3, AD=5, DC=? Click to expand... Recall a theorem that says "The altitude drawn to the hypotenuse of a right triangle is the geometric mean between the segments on the hypotenuse." That means \(\displaystyle \frac{3}{5}=\frac{5}{DC}\)
zzlady12 said: Given triangle ABC with right angle <BAC AD perpendicular to BC BD= 3, AD=5, DC=? Click to expand... Recall a theorem that says "The altitude drawn to the hypotenuse of a right triangle is the geometric mean between the segments on the hypotenuse." That means \(\displaystyle \frac{3}{5}=\frac{5}{DC}\)
