graph

tmac324

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Sep 29, 2009
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each sunday, anewspaper agency sells x copies of a certain newspaper for $1.25 per copy. the cost to the agency for each newspaper is $.50. the agency pays a fixed cost for storage,delivry and so on of $90 per sunday. how many copies of the newspaper need to be sold for the agency to break even? graph your result
 
I guess you can just make two T charts with one equation for each.
One chart would be the x(1.25) = total money
The other would be x(.50) + $90=total money
So then you would keep pluging the x with the # of newspapers and eventually you would get to the point they break even.
Thats the way I would do, but if there is a shorter way then one of the other users would help.
 
tmac324 said:
each sunday, anewspaper agency sells x copies of a certain newspaper for $1.25 per copy. the cost to the agency for each newspaper is $.50. the agency pays a fixed cost for storage,delivry and so on of $90 per sunday. how many copies of the newspaper need to be sold for the agency to break even? graph your result

Start by defining your variable.

Let x = number of newspapers sold

Now, we know this: the paper agency gets $1.25 for each copy of the newspaper it sells. If it sells "x" copies of the paper, then
revenue = 1.25x

And we know that the cost to the agency for each paper is $0.50, so for "x" papers, it will cost the agency 0.50x. And, the agency has some fixed costs that amount to $90 for each Sunday. Maybe you did not type the complete problem??? I see no other reference to Sunday. Is that the only day they sell the paper???

total cost = 0.50x + 90

The agency will break even when

revenue = total cost

1.25x = 0.50x + 90

You can solve that for x, which will be the number of newspapers the agency must sell to break even.

For the graphing part, you have two equations:
revenue = 1.25x.................and you can write this as y = 1.25x for graphing purposes.
total cost = 0.50x + 90............or, for graphing purposes, y = 0.50x + 90

Graph the two equations on the same set of axes. The point where the graphs intersect represents the "break-even point."
 
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