H Area

samaysahu123

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Joined
Oct 29, 2015
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THE "H' HAS been formed by removing two 2 *4 rectangles from the top middle and bottom middle ofa 6*10 rectangle.The H is completely tiles with tiles 1*1 which came in boxes of 6.What is the fewest number of boxes of tiles that must be purchased to tile the H
 
THE "H' HAS been formed by removing two 2 *4 rectangles from the top middle and bottom middle ofa 6*10 rectangle.The H is completely tiles with tiles 1*1 which came in boxes of 6.What is the fewest number of boxes of tiles that must be purchased to tile the H
I'm guessing that you're talking about something along the lines of the following:

Code:
*---*---*       *---*---*
|   |   |       |   |   |
*---*---*       *---*---*
|   |   |       |   |   |
*---*---*       *---*---*
|   |   |       |   |   |
*---*---*       *---*---*
|   |   |       |   |   |
*---*---*---*---*---*---*
|   |   |   |   |   |   |
*---*---*---*---*---*---*
|   |   |   |   |   |   |
*---*---*---*---*---*---*
|   |   |       |   |   |
*---*---*       *---*---*
|   |   |       |   |   |
*---*---*       *---*---*
|   |   |       |   |   |
*---*---*       *---*---*
|   |   |       |   |   |
*---*---*       *---*---*
And you're needing to figure out how many tiles you need to re-fill those holes.

Try counting the missing squares. Then divide by six to figure out how many sets of six you need. (Any remainder, of course, will indicate an extra box, not all of whose tiles you'll use).

If you get stuck, please reply showing all of your work so far. Thank you! ;)
 
hello so H withut gaps = 6*10 = 60 area = so tiles needed is 10 boxes
h with gaps = (4*2)*4 + 6*2=32+12= 44 Area= 8 boxes of tiles will cover the area
 
hello so H withut gaps = 6*10 = 60 area = so tiles needed is 10 boxes
h with gaps = (4*2)*4 + 6*2=32+12= 44 Area= 8 boxes of tiles will cover the area
If I understand you correctly, you are saying that the entire area containing the H figure is six units by ten units, so the entire area is 60 units. Then, to find the area of the H figure, you subtracted the area of the tiles removed to form the H figure, being twice two-by-four, or twice eight, which is sixteen. You subtracted this from the total area to obtain 60 - 16 = 44 square units. You then divided this by six (being the number of units per box) to obtain seven, plus two left over. This overage will require another box, meaning that you need eight boxes, and you'll have four units remaining when you're done.

If you meant something like the above, then yes, your answer is correct.
 
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