Help Please: tan[2sin^-1(-12/13)]. What I did was solve the triple, but...

[fish]

tan[2sin^-1(-12/13)]. What I did was solve the triple, but I don't know how to apply what I know to the problem.

 

[Deleted member 4993]

tan[2sin^-1(-12/13)]. What I did was solve the triple, but I don't know how to apply what I know to the problem.

Let

sin^-1(-12/13) = Θ → sin(Θ) = - 12/13 → tan(Θ) = ? then tan(2Θ) = ?