craycrayfangirl
New member
- Joined
- Jan 24, 2013
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- 1
Ok, so i have no idea what to do for this problem, and im extremely frustrated. I missed the lesson for this section 
heres the problem:
The sine, cosine and tangent ratios each have a reciprocal ratio. The reciprocal ratios are cosecant (csc), secant (sec), and cotangent(cot). Use triangle ABC (AB=15, BC=12, AC=9) and the definitions below to write each ratio.
csc X= 1/sin X sec X= 1/cos X cot X= 1/tan X
find: csc A
cot A
sec B
heres the problem:
The sine, cosine and tangent ratios each have a reciprocal ratio. The reciprocal ratios are cosecant (csc), secant (sec), and cotangent(cot). Use triangle ABC (AB=15, BC=12, AC=9) and the definitions below to write each ratio.
csc X= 1/sin X sec X= 1/cos X cot X= 1/tan X
find: csc A
cot A
sec B