If circle's center is at (0,0) and d = 6, then which point lies on circle?

[jejo1]

If the center of a circle is (0,0) and it's diameter = 6 units. Then the point which belongs to the circle is
{(6,0),(0,6),(root of 8,1),(1,root of 5)
I wan't to know how is it calculated.

 

[Deleted member 4993]

If the center of a circle is (0,0) and it's diameter = 6 units. Then the point which belongs to the circle is
{(6,0),(0,6),(root of 8,1),(1,root of 5)
I wan't to know how is it calculated.

The equation of the circle is:

x² + y² = 3²

Now continue....

 

[pka]

If the center of a circle is (0,0) and it's diameter = 6 units. Then the point which belongs to the circle is
{(6,0),(0,6),(root of 8,1),(1,root of 5)
I wan't to know how is it calculated.

@Lookagain, I took your advive. This is posted in trigonometry.

That is a false statement if the diameter is six units.
That is a true statement if the radius is six units.

The points on that circle are \(\displaystyle (3\cos(t),3\sin(t))\) for \(\displaystyle -\pi <t\le\pi\).

 

[stapel]

If the center of a circle is (0,0) and it's diameter = 6 units. Then the point which belongs to the circle is
{(6,0),(0,6),(root of 8,1),(1,root of 5)
I want to know how is it calculated.

To learn how to relate a circle's radius to that circle's diameter, try here. To learn how to relate a circle, its radius, its center, and its equation, try here. To learn how to figure out if a given point lies on a given circle, try here.

Once you have studied at least two lessons from each link, please attempt the exercise. You'll start by figuring out what the radius is. Then you can figure out what the equation is. Then you can test the listed points.

If you get stuck, you can then reply with a clear listing of your efforts so far, so we can see where things are going sideways. Thank you!