In the triangle ABC, if a = [2[b^2 - c^2]/[-b + sqrt[b^2 + 4c^2]...

[Ahmedmaths2010]

In the triangle ABC, if a = [2[b^2 - c^2]/[-b + sqrt[b^2 + 4c^2],
* prove that 3m(<C) = 2m(<B).

 

[stapel]

In the triangle ABC, if a = [2[b^2 - c^2]/[-b + sqrt[b^2 + 4c^2],
* prove that 3m(<C) = 2m(<B).

You have two unmatched brackets, noted above. Please reply with corrections. In particular, did you mean the following?

. . . . .\(\displaystyle a\, =\, \dfrac{2\, (b^2\, -\, c^2)}{-b\, +\, \sqrt{b^2\, +\, 4c^2\,}}\)

Also, are "a", "b", and "c" the lengths of the sides opposite the angles at vertices A, B, and C, respectively?

When you reply, please include your thoughts and efforts so far, including any theorems, etc, which you think might apply. Thank you!