Intermediate Algebra: radical 83 = 166, radical 48 = 96

[Helen]

This is a rectangle.
length = radical 83 = 166
width = radical 48 = 96
what is the best estimate for its area?
I did this. L = radical 83 with radical 85 = 9
w = radical 48 with radical 49 = 7
Do I multiply 9 * 7 to equal 63?
Is that the best estimate for its area?

 

[stapel]

This is a rectangle.
length = radical 83 = 166
width = radical 48 = 96
what is the best estimate for its area?

Um... So you have a rectangle, with values provided for the length and the width, and you are asked to find the area...? :?:

The area A of a rectangle width w and lenght L is found by multiplication:

. . . . .A = wL

But....

:arrow: The square root of 83 is not 166, and the square root of 48 is not 96. Whoever told you that "the square root of x" means "multiply x by 2" has badly mislead you. :shock:

To learn what square roots are and how they work, please review some online lessons. :idea:

Eliz.

 

[Helen]

Eliz,
I do know the square roots. I just got confused at the end.
Thank you. I will keep trying. Helen

 

[Helen]

Eliz,
The example I was going by is this.
Approximate the length (radical 192) with (radical 196) = 14
14 * 14 = 196
width = (radical 48) with (radical 49) = 7
7 * 7 = 49
The best estimate for rectangle dimensions are 14 by 7.
The estimate for the perimeter is
2 * 14 + 2 * 7
= 28 + 14
= 42
Mine, ( the one that I did before), is still not right. Helen

 

[Deleted member 4993]

This is a rectangle.
length = radical 83 = 166
width = radical 48 = 96
what is the best estimate for its area?
I did this. L = radical 83 with radical 85 = 9
w = radical 48 with radical 49 = 7
Do I multiply 9 * 7 to equal 63?
Is that the best estimate for its area?

The best estimate - without using calculator - seems to be 63 (even though you have several typos) - and the answer is correct.

 

[Helen]

Subhotosh Kahn,
Thank you for your help. Helen