Need help with angles!

Csvictory14

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Oct 30, 2011
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Four of the exterior angles of a hexagon are 93, 50, 37 and 85. The other two angles are equal, work out the size of these equal exterior angles.
I know that they must add up to 360 so my first thought was to add 93, 50, 37 and 85 then subract the answer from 360 and then divide by two but that is probably wrong, any ideas?
 
@CSVictory14
The sum of the exterior angles of any polygon will always equal to 360
Therefore your theory is right
You add up the angles which will give you
93 + 50 + 37 + 85 = 265
So you let one of the unknown angles be x. Therefore
x + x + 93 + 50 + 37 + 85 = 360 (They're all the exterior angles)
2x + 265 = 360
2x = 360-265
2x = 95
x = 95/2
x = 47.5
So the two unknown angles are 47.5...
Don't forget to add the degrees symbols.
 
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