Please check my maths to see if it is correct. Thank you.

S

Subliminal

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Sep 11, 2015
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Hello,
I'd like someone to double check my maths please, it wasn't the greatest at school and that was a few years ago!
If I am incorrect could you please tell me the correct answer as well as show me how to apply it so I can figure out similar problems myself. Thanks.


Yes, this is about Pokémon, but there is a lot of maths involved. Here goes:


PROBLEM 1:
For a Pokemon to be "shiny" the odds are 1/273 encounters.
Each encounter has the chance for "Pokemon A" to appear of 60% OR"Pokemon B" to appear of 40%.


The odds of having Pokemon A appear shiny are 1/455
I multiplied 1/273 by 6/10 to result in 1/455.
The odds of having Pokemon B appear shiny are 2/1365
I multiplied 1/273 by 4/10 to result in 2/1365.


PROBLEM 2:
For a Pokemon to be shiny the odds are 1/273 encounters.
5 Pokemon appear in each encounter and always 5, never more, never less. Each has the same odds of being shiny.


The chance that two Pokemon will be shiny in a single encounter are 1/74529
I squared/ multiplied by the power of 2, 273 to result in 1/74529


Applying this maths, the chance of all 5 to be shiny will be 273 to the power of 5?


PROBLEM 3:
I am unsure how to work this one out.
For a Pokemon to be shiny the odds are 1/273 encounters.
Each encounter has the chance for Pokemon A to appear of 60% OR Pokemon B to appear of 40%.
Pokemon A and B both have a 50% chance to be MALE and 50% chance to be FEMALE.


What are the chances of encountering a FEMALE Shiny Pokemon A?


Please let me know if my maths is correct, if it isn't please correct me and show me how to apply it too.


Many thanks!!
 
Your math for parts 1 and 2 seem fine to me. Those are the answers I get. And for part 3, you already know the probability of finding a shiny Pokemon A, from solving part 1. The problem tells you that both Pokemon species are evenly split by sex - half male, half female. So what is the probability of a random Pokemon being both female and species A? As a hint, try a similar, easier problem. Let's say you have a normal set of 52 playing cards. That means the probability of the top card being a Spade is 1 in 4. And the probability of the top card being a Jack is 1 in 13. So, then what is the probability of the top card being the Jack of Spades?

P.S. mostly unrelated, but just wanted to point out that in the Pokemon games, the actual odds of finding a shiny Pokemon is 1 in 8192 :p
 
Thank you for your answering my question with another question. I used a different website and they were more than helpful. The base odds are 1/8192, however that was halved to 1/4096 in Omega Ruby and Alpha Sapphire. The Shiny Charm increases the chance of finding a Shiny Pokémon by 300%, and horde encounters by 500% (as you see 5 Pokémon). So, with the Shiny Charm it's 1/273 in horde encounters in ORAS, not 1/8192.

ksdhart said:
P.S. mostly unrelated, but just wanted to point out that in the Pokemon games, the actual odds of finding a shiny Pokemon is 1 in 8192 :p
Click to expand...
 
Subliminal said:
Thank you for your answering my question with another question. I used a different website and they were more than helpful.
Click to expand...
Yes, the other place did do all the work and hand you the completed solution. It had been assumed on this forum that you'd wanted to learn. This is why the helper here asked you a leading question (that is, a question which was intended to lead you toward finding your answer). Sorry. :oops:
 
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