Polynomial Problem - Please Help!

[NovErdy]

Hello, please help me in this problem:

p(x) = (3x + 5)(x^2 - t)
q(x) = (2x^4 - 7x^3 - 5) - (x^2 + 8x + 12)
If p(x) is congruent to q(x) , then the value of t is...

a. -10
b. -5
c. -2
d. 2
e. 10

I haven't figured how to do it. And if I posted this in the wrong subforum, please tell me.

Thanks in advance!

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[Deleted member 4993]

Hello, please help me in this problem:

p(x) = (3x + 5)(x^2 - t)
q(x) = (2x^4 - 7x^3 - 5) - (x^2 + 8x + 12)
If p(x) is congruent to q(x) , then the value of t is...

a. -10
b. -5
c. -2
d. 2
e. 10

I haven't figured how to do it. And if I posted this in the wrong subforum, please tell me.

Thanks in advance!

Sent from my CPH1803 using Tapatalk

Please check your post for correctness.

p(x) - as posted - is a 3rd order polynomial.

q(x) - as posted - is a 4th order polynomial.

Those two cannot be "congruent". Those can intersect each other - when "t" is a number.

 

[NovErdy]

Please check your post for correctness.

p(x) - as posted - is a 3rd order polynomial.

q(x) - as posted - is a 4th order polynomial.

Those two cannot be "congruent". Those can intersect each other - when "t" is a number.

Yeah, I am aware of this. I just want to check whether I was right, because my teacher says there's an answer for this question.

Thanks!

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[Dr.Peterson]

Hello, please help me in this problem:

p(x) = (3x + 5)(x^2 - t)
q(x) = (2x^4 - 7x^3 - 5) - (x^2 + 8x + 12)
If p(x) is congruent to q(x) , then the value of t is...

a. -10
b. -5
c. -2
d. 2
e. 10

I haven't figured how to do it.

Please explain the relevant definition of "congruent", and the context of the problem. What topic have you been studying? Also, of course, make sure you copied the entire problem exactly as given to you.

 

[NovErdy]

Please explain the relevant definition of "congruent", and the context of the problem. What topic have you been studying? Also, of course, make sure you copied the entire problem exactly as given to you.

I am sorry, but I am hitting the language barrier here. The topic is "Equality of polynomial". And yes, I've copied the entire problem.

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[Dr.Peterson]

I am sorry, but I am hitting the language barrier here. The topic is "Equality of polynomial". And yes, I've copied the entire problem.

You're saying that the problem used the word "congruent", but meant "equal"? Are you translating from another language?

As Subhotosh Khan said, these polynomials can't be equal (that is, can't have the same value for all x), regardless of the value of t, because one has degree 3 and the other has degree 4. So the problem has no solution.