themathman
New member
- Joined
- Sep 8, 2019
- Messages
- 10
I am having trouble trying to prove that a function y=x^1/2, x>0 is strictly concave. I am not sure how to start this question off.
I think you meant, as stated here, that "concave" is the same as "concave downward". It always feels backward to me, even though I know the reason ...A function is "concave" (strictly speaking "concave upward" which is the same as "convex downward") if its second derivative is positive. What is the second derivative of \(\displaystyle x^{1/2}\)?