Pythagoriean Triples

[Juniper_Berry101]

Well, the thing is the picture in my book isn't telling me anything. So I have A triangle and it's bisected. Now each of the bases equals 8 and the height is x. It tell me nothing more so is my problem

16 squared + X squared = X squared


HUH!!!!!!!!!!!??????????

 

[Mrspi]

Well, the thing is the picture in my book isn't telling me anything. So I have A triangle and it's bisected. Now each of the bases equals 8 and the height is x. It tell me nothing more so is my problem

16 squared + X squared = X squared


HUH!!!!!!!!!!!??????????

I'm sorry...before I would even attempt to help you, I'd need a MUCH clearer explanation of what your problem is.


"A triangle and it's bisected" isn't clear.

And you have not asked a specific question. What are you asked to find? The height of the triangle (which you've called x?) I think there's some important information that we're missing.

 

[mmm4444bot]

Maybe the original poster has somehow been told that 8, x and the hypotenuse form a Pythagorean Triple? That would make x = 6. I'm totally guessing.

 

[tutor_joel]

I'm thinking Isosceles triangle with a base of 16 and an unknown height x. with angles a and b unknown,

the 3 legs of 1 of the two triangles from the bisection are

8, x and via the Pythagorean theorem, sqrt(8^2 + x^2)

using trig, sin(a) = cos(b)

When is this true? That should get you started if it's an isosceles, It's easier if it's an equilateral.