Radicals

[JojoBear94]

I need more help

Simplifying radicals.

Mulitplying radicals.

Simplifying radicals in fraction form.

Simplifying radicals with addition/subtraction (i don't know how else to describe it)
Ex: 2(radical)7-5(radical)7

 

[Denis]

All here...and just for you! :

http://www.purplemath.com/modules/radicals.htm

 

[JeffWest]

I can give you some examples of radical simplification. Try them before you look at the solution. To view the solution simply click over the black bar under each example:

1. \(\displaystyle \sqrt{12}\)

Spoiler: :2j373dsd

\(\displaystyle \sqrt{12}=\sqrt{4*3}=\sqrt{2^2*3}=\sqrt{2^2}\sqrt{3}=2\sqrt{3}\)[/spoiler:2j373dsd]

2.\(\displaystyle 4\sqrt{32}+8\sqrt{18}\)

Spoiler: :2j373dsd

\(\displaystyle 4\sqrt{32}+8\sqrt{18}=4\sqrt{4^2*2}+8\sqrt{3^2*2}=16\sqrt{2}+24\sqrt{2}=(16+24)\sqrt{2}=40\sqrt{2}\)[/spoiler:2j373dsd]

3. \(\displaystyle \frac{4}{\sqrt{6}}-\frac{\sqrt{6}}{6}\)

Spoiler: :2j373dsd

\(\displaystyle \frac{4}{\sqrt{6}}-\frac{\sqrt{6}}{6}=\frac{4}{\sqrt{6}}\frac{\sqrt{6}}{\sqrt{6}}-\frac{\sqrt{6}}{6}=\frac{4\sqrt{6}}{\sqrt{6*6}}-\frac{\sqrt{6}}{6}=\frac{4\sqrt{6}}{6}-\frac{\sqrt{6}}{6}=\frac{3\sqrt{6}}{6}=\frac{\sqrt{6}}{2}\)[/spoiler:2j373dsd]