Simplify ((a^3+4a)/(a^2-16))/((a^2+8a+15)/(a^2+a-20))
E evan399 New member Joined Sep 24, 2007 Messages 39 Oct 29, 2007 #1 Simplify ((a^3+4a)/(a^2-16))/((a^2+8a+15)/(a^2+a-20))
D Deleted member 4993 Guest Oct 29, 2007 #2 Re: Simplify evan399 said: ((a^3+4a)/(a^2-16))/((a^2+8a+15)/(a^2+a-20)) Click to expand... Please show your work - and indicate exactly where you are stuck. To start off - factorize the terms and cancel out common terms - if possible.
Re: Simplify evan399 said: ((a^3+4a)/(a^2-16))/((a^2+8a+15)/(a^2+a-20)) Click to expand... Please show your work - and indicate exactly where you are stuck. To start off - factorize the terms and cancel out common terms - if possible.
L Loren Senior Member Joined Aug 28, 2007 Messages 1,299 Oct 29, 2007 #3 ((a^3+4a)/(a^2-16))/((a^2+8a+15)/(a^2+a-20)) = \(\displaystyle \frac{a^3+4a}{a^2-16}\times \frac{a^2+a-20}{a^2+8a+15}\) Now, factor and simplify.
((a^3+4a)/(a^2-16))/((a^2+8a+15)/(a^2+a-20)) = \(\displaystyle \frac{a^3+4a}{a^2-16}\times \frac{a^2+a-20}{a^2+8a+15}\) Now, factor and simplify.
E evan399 New member Joined Sep 24, 2007 Messages 39 Oct 30, 2007 #4 Is the answer (a(a^2+4))/((a+4)(a+3))
stapel Super Moderator Staff member Joined Feb 4, 2004 Messages 16,582 Oct 30, 2007 #5 That's what I'm getting. Eliz.