sin2x+sinx=0 over the interval [0,2pie)
G Grayson New member Joined Nov 17, 2011 Messages 1 Nov 17, 2011 #1 sin2x+sinx=0 over the interval [0,2pie)
tkhunny Moderator Staff member Joined Apr 12, 2005 Messages 11,339 Nov 17, 2011 #2 Have you considered factoring? sin(x) * (sin(x) + 1) = 0 Now what? By the way, 'pie' is for eating, 'pi' is for mathematics and greek spelling.
Have you considered factoring? sin(x) * (sin(x) + 1) = 0 Now what? By the way, 'pie' is for eating, 'pi' is for mathematics and greek spelling.
