Trigonometry: If asin x=bcos x=ctan 2x and (a2-b2)2=kc2(a2+b2) then k=?

If asin x=bcos x=ctan 2x and (a2-b2)2=kc2(a2+b2) then k=?
Hint:

tan(2x) = [2*tan(x)]/[1 - tan2(x)]

a * sin(x) = b * cos(x) → tan(x) = ?

continue.....
 
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