Trigonometry problem

[sailor79]

Hi,
I'm lacking enough math knowledge to solve this probably simple problem.
I need to solve the following formula for y:

x = (180/PI) * Ln(tan(45 + y/2))

Hope someone can help me here.

 

[Deleted member 4993]

Hi,
I'm lacking enough math knowledge to solve this probably simple problem.
I need to solve the following formula for y:

x = (180/PI) * Ln(tan(45 + y/2))

Hope someone can help me here.

Have you learned inverse operations:

Inverse of addition is subtraction.

Inverse of multiplication is division.

Inverse of logarithm [Ln(x)] is exponential (e^x).

Inverse of tangent function[tan(x)] is tan_inverse function [tan^-1(x)].

You will have to use these ...... it will look complicated but straight-forward operation.

Start with:

\(\displaystyle x = \frac{180}{\pi}*Ln[tan(45+\frac{y}{2})]\)

\(\displaystyle x * \frac{\pi}{180} \ = \ Ln[tan(45+\frac{y}{2})]\)

Now invert LN .... then invert tan.... and so on....