palominoinHim
New member
- Joined
- Jan 24, 2013
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Thank you for any input on how I can word this in statements and reasons!!!
Prove that a circle described on the hypotenuse of a right triangle as a diameter passes through the vertex of the right angle. I'm using circle O, right triangle ABC, and diameter BC. :idea: Figured out so far that arcs BC and BC' are semicircles, angle BAC equals 90 degrees (genius, right?
), and Corollary 42-2 says that an angle inscribed in a segment whose arc is equal to a semicircle is a right angle; which matches up with the 90 degrees thingy. My question for you amazingly awesome Einsteins is: how would I word the converse of Theorem 42 in a way that actually remotely makes sense? Again, props to everyone who helps at all; I really appreciate you.
Prove that a circle described on the hypotenuse of a right triangle as a diameter passes through the vertex of the right angle. I'm using circle O, right triangle ABC, and diameter BC. :idea: Figured out so far that arcs BC and BC' are semicircles, angle BAC equals 90 degrees (genius, right?