Vector(math): Finding the force of R and F

Wiz

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I'm in Y10 and my subject for math is currently vector. I have attached the screen shot of the problem below. I tried simply trigonometry yet I'm not able to solve it. Can someone explain how can this problem be solved? Thanks!
 

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  • Screen Shot 2015-11-15 at 7.23.42 PM.png
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I'm in Y10 and my subject for math is currently vector. I have attached the screen shot of the problem below. I tried simply trigonometry yet I'm not able to solve it. Can someone explain how can this problem be solved? Thanks!

attachment.php

The best way would be to define x-y axes along F and R - since those are perpendicular to each other.

Decompose the third vector along x and y.

Then apply equilibrium equations:

Sum of forces in x-direction = 0 , and,

Sum of forces in y-direction = 0

You'll have the solution.

For more explicit help - show us your work so that we know exactly where you are getting stuck!
 
attachment.php

The best way would be to define x-y axes along F and R - since those are perpendicular to each other.

Decompose the third vector along x and y.

Then apply equilibrium equations:

Sum of forces in x-direction = 0 , and,

Sum of forces in y-direction = 0

You'll have the solution.

For more explicit help - show us your work so that we know exactly where you are getting stuck!


Thanks for the quick reply!

I tried doing it myself following your instruction but I got stuck when attempting to calculate the x axis vector.

Here's what I did:
I calculated the vector R by shifting the 600n along the y axis of vector R by: 180°-165°=15° then Z=600 x cos15°=579.56 then using the equilibrium equation R=579.56. Is this correct?

However I do not have a clue on how can F be solved. I tried shifting 600n to the x axis of F by the same method but I was not able to calculate the result. (Attached below)

I appreciate any help! :3
 

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  • rsz_20151115_205653.jpg
    rsz_20151115_205653.jpg
    300.4 KB · Views: 0
Thanks for the quick reply!

I tried doing it myself following your instruction but I got stuck when attempting to calculate the x axis vector.

Here's what I did:
I calculated the vector R by shifting the 600n along the y axis of vector R by: 180°-165°=15° then Z=600 x cos15°=579.56 then using the equilibrium equation R=579.56. Is this correct?

However I do not have a clue on how can F be solved. I tried shifting 600n to the x axis of F by the same method but I was not able to calculate the result. (Attached below)

I appreciate any help! :3

For equilibrium in the x-direction:

F - 600*cos(75) = 0
 
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