ICPassionfruit said:
My daughter is in need of help if someone can help her to understand how to get the answer.
Thanks
Q: The area of equilateral triangle ABC is 12 cm2. What is the area of equilateral triangle DEF if the sides are two times as long as the sides of triangle ABC? Explain your Answer.
There's MUCH I don't know about what your daughter has studied, so I'm guessing at what she may (or may NOT) understand.
First of all, I assume she may be studying similar figures. ANY two equilateral triangles are similar...same shape.
Secondly, the AREAS of two similar figures have a ratio that is the square of the ratio of any pair of corresponding sides.
You are given two equilateral triangles, ABC and DEF. You are told that the sides of triangle DEF are two times as long as the sides of triangle ABC, so the ratio of one side of triangle ABC to the corresponding side of triangle DEF is 1/2.
If the ratio of a pair of corresponding sides is 1/2, then the ratio of the areas is (1/2)^2, or (1/2)*(1/2), or 1/4
So,
area of triangle ABC = (1/4)*area of triangle DEF
12 = (1/4) * area of triangle DEF
Can you take it from here?