Latest activity

  • logistic_guy
    logistic_guy replied to the thread temperature and oven.
    🫶🫶 \mu = \frac{\mu_1 + \mu_2 + \mu_3 + {\color{green} \mu_1} + {\color{green} \mu_2} + {\color{green}\mu_3} + {\color{green}\mu_4}}{7}...
  • G
    Gringo123 reacted to Ted's post in the thread Read Before Posting with Like Like.
    Welcome to Pufter.com! Please take the time to read the following before you make your first post. It will help you to get your...
  • L
    lookagain replied to the thread 100 Integrals.
    dy \ = \ 3sec^2(\theta) \ d(\theta)
  • K
    If you fumble - then you cannot score a touchdown (most of the time).
  • K
    khansaheb posted the thread I am all alone.... in News.
    .... other than those despicable bots (~500)
  • logistic_guy
    logistic_guy replied to the thread automorphism.
    To warm up the audience, we are honored to share this information: An automorphism of a field is a bijective field homomorphism from...
  • logistic_guy
    logistic_guy replied to the thread puzzle - 2.
    I found \textcolor{darkgreen}{\bold{Toronto}} \huge\textcolor{indigo}{\bold{the \ solution \ so \ far.}}
    • image37.jpg
  • logistic_guy
    logistic_guy replied to the thread microprocessor - 6.
    \bold{8.} Convert the following octal numbers into decimal: (b) 12.3 = 1\left(8^1\right) + 2\left(8^0\right) + 3\left(8^{-1}\right) =...
  • logistic_guy
    logistic_guy replied to the thread amplifier.
    If we solve for R_T, we get: R_T = \textcolor{blue}{100 \ \Omega}
  • logistic_guy
    logistic_guy replied to the thread IAS computer.
    We will also take these 20 bits and divide it. But not into half. 010\text{FA} \longrightarrow 20 bits 01\longrightarrow 8 bits...
  • logistic_guy
    logistic_guy replied to the thread palindrome.
    It is difficult to enter each digit of 98765 in the array. How to resolve this issue? We will use the hint given in the exercise. Now...
  • logistic_guy
    logistic_guy replied to the thread transistor - 2.
    :alien:👽 I_C = \beta I_B = 200 \times 610.5 \times 10^{-9} = 0.0001221 \ \text{A} = \textcolor{indigo}{122.1 \ \mu\text{A}}
Top