Areas: The company has won a contract to build a new sports and leisure center...
- Thread starter oli.dyer
- Start date
- Joined
- Feb 4, 2004
- Messages
- 16,582
For those (like me) who can't easily read sideways pictures, this is the relevant portion of text from one of the images:
The company has won a contract to build a new sports and leisure center in town and a number of separate groups have been established to work on different projects within the contract.
Group A are working on the outdoor throwing area and have sketched a plan for the various disciplines, which is shown in Appendix A. They need you to calculate the following and you should work in radians throughout.
(a) The area of turf needed for the hammer throw. (The throwing area - where the hammer is allowed to land.)
(b) The length of the painted line enclosing the throwing area for the hammer throw.
Group B are working on the drainage system from the park, which will have a 260mm-diameter drain.
(c) If the estimated depth of water is 90mm, determine the wetted perimeter of the drain and the cross-sectional area of the water.
No work appears to be shown in either image.
The company has won a contract to build a new sports and leisure center in town and a number of separate groups have been established to work on different projects within the contract.
Group A are working on the outdoor throwing area and have sketched a plan for the various disciplines, which is shown in Appendix A. They need you to calculate the following and you should work in radians throughout.
(a) The area of turf needed for the hammer throw. (The throwing area - where the hammer is allowed to land.)
(b) The length of the painted line enclosing the throwing area for the hammer throw.
Group B are working on the drainage system from the park, which will have a 260mm-diameter drain.
(c) If the estimated depth of water is 90mm, determine the wetted perimeter of the drain and the cross-sectional area of the water.
No work appears to be shown in either image.
- Joined
- Feb 4, 2004
- Messages
- 16,582
You've been given a sector of a circle. You've been given the central angle and the radius. You've memorized the formula for the area of a sector, given the central angle and the radius. Where are you stuck in the plug-n-chug?
You've been given the central angle and the radius for an arc. You've memorized the formula for arc length. Where are you stuck in the plug-n-chug?
I'm pretty sure we need more information for this. For instance, are we to assume that the drainpipe is lying on its side (so its central axis is horizontal), that the drain has the same orientation, and that it is lying level to the base of the catchment area, so the water in the drainpipe is exactly the same depth as the water in the catchment area?
When you reply, please include a clear listing of your thoughts and efforts so far. Thank you!
