Hello, moronatmath!
	
	
		
		
			An open box is to be made from a flat square piece of material 8 inches in length and width
by cutting equal squares of length x from the corners and folding up the sides.
Write the volume V of the box as a function of x.
Leave it as a product of factors; you do not have to multiply out the factors.
If we write the domain of the box as an open interval in the form (a,b),
then what is a? \(\displaystyle \;\) and what is b?
		
		
	 
From an 8-by-8 inch square, four congruent corners squares are removed.
	
	
	
		Code:
	
	
		      : x : 8-2x  : x :
      *---+-------+---*
      |::::       ::::| x
      + - * - - - * - +
      |   :       :   |
      |   :       :   | 8-2x
      |   :       :   |
      + - * - - - * - +
      |::::       ::::| x
      *---+-------+---*
      * x : 8-2x  : x *
	 
 The sides are folded up and an open-top box is formed:
	
	
	
		Code:
	
	
		              *-------------*
            / |           / | x
          /   *---------/   *
        /   /         /   /
      *-------------*   / 8-2x
    x |             | /
      *-------------*
           8-2x
	 
 The volume of a box is, of course: \(\displaystyle \:V\;=\;L\,\times\,W\,\times\,H\)
So we have: \(\displaystyle \:V\;=\;(8\,-\,2x)(8\,-\,2x)x \:=\:x(8\,-\,2x)^2\)
The domain of \(\displaystyle x\) is: \(\displaystyle (0,\,4)\)
If \(\displaystyle x\) (side of the removed square) is 0, no squares are removed.
\(\displaystyle \;\;\)There are no "sides" to fold up.
\(\displaystyle \;\;\)The volume of the so-called box would be 0.
If \(\displaystyle x\,=\,4\), we have removed 
all of the original square.
\(\displaystyle \;\;\)There is no material to form the box, so its volume is 0.
Hence, the value of \(\displaystyle x\) must lie 
between 0 and 4.