Can someone help me with two problems with the substitution method

Do not post the same question twice, even in different subforums.
 
Melissavaldes15 said:
X-2y=10
-4x-3y=37



-4x+y=10
3x+3y=15


Slove the system of linear equations by using substitutional method
Click to expand...
First, you want to solve for either X or Y, the very first one will probably be the easiest because X is by itself.
So, add the 2Y over and you get X=2Y+10
Plug that in where the X is on the next equation, so -4(2Y+10) -3Y=37
Solve, -11Y-40=37... -11Y=77... Y=-7
Now, plug in -7 for the Y in the first equation, X-2(-7)=10
And solve, X+14=10, X=-4


I trust you can figure out how to do the next one on your own
 
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