Can you help me.

vinceman

New member
Joined
Oct 17, 2005
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13
The length of a rectangle is 2ft more than the width. find the minimum dimensions if the perimeter is more than 16ft and the length and width are integers.

x= length, w= width

|p|w+2>16

|p|w+2>16 or |p|w+2<-16
-2 -2 -2 -2

|p|w>14 or |p|w<-14

can you help me from here?
 
I'm sorry, but I don't follow your notation. What does "absolute value of p" represent? If "x" is "length", where do you use it in your work? Why is the width "w" multiplied by the absolute value of p?

I would approach the exercise as follows:

. . . . .For a rectangle with width "w" and the length "L", the perimeter P is:

. . . . .P = 2L + 2w

. . . . .We are given:

. . . . .P > 16

. . . . .Then:

. . . . .16 < 2L + 2w
. . . . .8 < L + w

. . . . .Also, we are given:

. . . . .L = w + 2

Now substitute and simplify. Then solve for the minimum value of "w", and back-solve for the corresponding value of "L".

Eliz.
 
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