Given triangle ABC, the median BE intersect the angle bisector of angle C in the point F. With B as the centre, the circle through F cuts the side AB at G. The perpendicular to BC through point C, cuts BE produced at H. The line, parallel to EB, through point G, cuts AC at M and HC at N.
Friends kindly, help, do you think I understood the question correctly; this is what I did. I drew a circle, constructed an ISOSCELES triangle, with vertex B at the centre of the circle, forming leg BA anticlockwise, and BC forming leg of the triangle clockwise. AC as the base. From B constructed a perpendicular to E, produced at E to H, from H drew a tangent from H passing C to form N. Thanks friends for you time!
Friends kindly, help, do you think I understood the question correctly; this is what I did. I drew a circle, constructed an ISOSCELES triangle, with vertex B at the centre of the circle, forming leg BA anticlockwise, and BC forming leg of the triangle clockwise. AC as the base. From B constructed a perpendicular to E, produced at E to H, from H drew a tangent from H passing C to form N. Thanks friends for you time!