coordinated geomatry

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kaleem

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the line 3x+4y=24 cut x axix and y axix at pt a and pt b find its coordinates ,the point c on the line such that c is acquittance from x and y axix. and the equation of line oc where o is origin.
 

1. ֺֺֺ Post the exercise or your question completely and accurately.
the line 3x+4y=24 cut x axix and y axix at pt a and pt b find its coordinates ,the point c on the line such that c is acquittance from x and y axix. and the equation of line oc where o is origin.
Click to expand...

Is the following correct?
the line 3x+4y=24 cuts the x axis and y axis at pt a and pt b.
a) find the coordinates of pt a and pt b,
the point c is on the line such that c is equidistant from the x and y axis.
b) find the equation of line oc where o is origin.

2. ֺ Tell us something about your age and math education.
Why did you use the words that you did? Was this problem given to you by voice?, written?

3. ֺ Please show any work (even if you think it's wrong)


4. ֺ We may respond by asking you some questions. Please try to answer our questions.
 
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cordinate geomatry

ref above , question is ok but we also have to find the coordinates of pt c such that it is equidistant from x xix and y axix.
 
cordinate geomatry

REF QUESTION,i am a parent. this is a question of d3 math book o level.exer 4c.
from the equation for cord pt A
3x+4x=24
3x+4(0)=24
x=24
A=(8,0)
for pt B
3(0)+44=24
y=24/4=6
B=(0,6)

THE FIRST PART a is solved ,now the problem is how to find coordinates of point c
 
cordinate geomatry

Dear Bob Brown thanks for your kind response.i am a parent age 44 math is studied upto 14 grade.ref above solution quest x=8 not 24
 
kaleem said:
REF QUESTION,i am a parent. this is a question of d3 math book o level.exer 4c.
from the equation for cord pt A
3x+4x=24
Click to expand...
you mean 3x+ 4y= 24

3x+4(0)=24
x=24
Click to expand...
You mean x= 8

A=(8,0)
for pt B
3(0)+44=24
Click to expand...
you mean 4y

y=24/4=6
B=(0,6)

THE FIRST PART a is solved ,now the problem is how to find coordinates of point c
Click to expand...
The distance from point (x, y) to the x and y axes are, respectively, y and x. so a point "equidistant from the x and y axes" satisfies y= x. Find where y= x and 3x+ 4y= 24 intersect.
 
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coordinate geomatry

DEAR HALLSOFY,

the answer of this question i mean to find the quardinates of pt c is 24/7 but how i a m trying to find.of course the point c will have quardinates x,y but we have to find the value.
 
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the line 3x+4y=24 cuts the x axis and y axis at pt a and pt b.
a) find the coordinates of pt a and pt b,
the point c is on the line such that c is equidistant from the x and y axis.
b) find the equation of line oc where o is origin.
Click to expand...

a) a=[8,0] b=[0,6] c=[24/7, 24/7]

b) If a line OC goes through the origin then ALL points on OC have y=x.


You did not have to calculate point c to answer part b.
All you need to know is that it goes through the origin and ANY point "equidistant from the x and y axis"
Do you see why?
 
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change?

kaleem said:
Dear Bob Brown thanks for your kind response.i am a parent age 44 math is studied upto 14 grade.ref above solution quest x=8 not 24
Click to expand...

kaleem,

I'm sorry but I did not understand this.
If it is a correction, then re-state the entire problem.

Or perhaps you have enough now to do it.
 
cordinate geomatry

DEAR BOB
ALTHOUGH THIS QUESTION IS SOLVED BUT I STILL DONT UNDER STAND HOW.


PL LOOK AND HELP

x1/8=(6-y1)/6
6x1=8(6-y1)
3x1=24-4y1
as x1=y1
3y1=24-4y1
y1=24/7
x1=24/7
pl explain how it is solved

thanks
 
cordinate geomatry

dear bob i am repeating the whole question

THE LINE 3X+4Y=24 CUTS THE X-AXIX AT POINT A AND Y AXIX AT POINT B FIND

a THE COORDINATES OF A AND B

b THE POINT C ON THE LINE SUCH THAT C IS EQUIDISTANCE FROM THE X AXIX AND Y AXIX

c THE EQUATION OF THE LINE OC WHERE O IS THE ORIGIN.
 
kaleem said:
dear bob i am repeating the whole question

THE LINE 3X+4Y=24 CUTS THE X-AXIX AT POINT A AND Y AXIX AT POINT B FIND

a THE COORDINATES OF A AND B

b THE POINT C ON THE LINE SUCH THAT C IS EQUIDISTANCE FROM THE X AXIX AND Y AXIX

c THE EQUATION OF THE LINE OC WHERE O IS THE ORIGIN.
Click to expand...
The
b) question asks for point c coordinates.
c) question asks for line OC.

I will tell how I would do part b)

FIRST do part c) it is easy and obviously y=x
SECOND see that the desired point satisfies both equations.
3X+4Y=24 is given
3x+4x =24 because y=x
7x=24
x=24/7
 
Greetings!

The x and y coordinates of C must be same as the point is equidistant from both axes, therefore y=x value will be substituted in line 'l' equation (3x+4(x) = 24), this will give a 3 whole 3/7. Hence, the coordinates will be (3 3/7 , 3 3/7)

For the next part we have the points of C and the origin which is (0,0)
The standard formulae of y=mx+c can be used or y-y1 = y2-y1/x2-x1 (x-x1) to generate the equation

Hope this helps :))
 
Amnah Irfan said:
Greetings!

The x and y coordinates of C must be same as the point is equidistant from both axes, therefore y=x value will be substituted in line 'l' equation (3x+4(x) = 24), this will give a 3 whole 3/7. Hence, the coordinates will be (3 3/7 , 3 3/7)

For the next part we have the points of C and the origin which is (0,0)
The standard formulae of y=mx+c can be used or y-y1 = y2-y1/x2-x1 (x-x1) to generate the equation

Hope this helps :))
Click to expand...
You are trying to answer ~10 yr old query. The original poster did not revisit the site in last ~10 yrs.
 
Amnah Irfan said:
y-y1 = y2-y1/x2-x1 (x-x1)
Click to expand...


Also, you are missing required grouping symbols. And an added pair of brackets
is good for clarification/emphasis, and so is extra spacing for helping readability:

\(\displaystyle y - y_1 \ = \ [(y_2 - y_1)/(x_2 - x_1)](x - x_1) \)
 
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